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3. Furthermore, if you will adde the broken numbers of broken togi∣ther, as to adde the ⅔ of ¾ of ⅘ with the ⅚ of ½ of ⅝: first you must reduce ye nū∣bers according to ye order of ye fourth reduction, in multiplying the nume∣rator of the fyrst 3. fractions, the one by the other, and of the product make your numerator, & likewise you must multiplie ye denominators of ye fore∣said thre fractions, ye one by the other
and of the product make your deno∣minator, and you shal finde 24/60 for the fyrst thre broken numbers, which be∣ing abbreuied do make ⅖, thē reduce the other 3. fractiōs, by ye saide fourth reduction, in multiplying the nume∣rators by numerators, & denomina∣tors, by denominators, as you did by the first 3. broken numbers, & you shal finde 25/96 thē must you adde yt ⅖ which came of the fyrst 3. broken numbers, & 25/96 which are of the last 3. fractions, both togither, by the instruction of ye first additiō & you shal find 317/480 which cannot be abbreuied, but is ye product of ye additiō: so much are the ⅔ of ¾ of ⅘ added with the ⅚ of ½ of ⅝ as hereaf∣ter by practise doth euidently appere.
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