Syntaxis mathematica, or, A construction of the harder problemes of geometry with so much of the conicks as is therefore requisite and other more ordinary and usefull propositions inter-mixed, and tables to several purposes / by Tho. Gibson.

About this Item

Title: Syntaxis mathematica, or, A construction of the harder problemes of geometry with so much of the conicks as is therefore requisite and other more ordinary and usefull propositions inter-mixed, and tables to several purposes / by Tho. Gibson.
Author: Gibson, Thomas, 17th/18th cent.
Publication: London :: Printed by R. & W. Leybourne for Andrew Crook,; 1655.
Rights/Permissions: This keyboarded and encoded edition of the work described above is co-owned by the institutions providing financial support to the Early English Books Online Text Creation Partnership. Searching, reading, printing, or downloading EEBO-TCP texts is reserved for the authorized users of these project partner institutions. Permission must be granted for subsequent distribution, in print or electronically, of this text, in whole or in part. Please contact project staff at eebotcp-info@umich.edu for further information or permissions.
Subject terms: Geometry -- Early works to 1800.
Cite this Item: "Syntaxis mathematica, or, A construction of the harder problemes of geometry with so much of the conicks as is therefore requisite and other more ordinary and usefull propositions inter-mixed, and tables to several purposes / by Tho. Gibson." In the digital collection Early English Books Online 2. https://name.umdl.umich.edu/A42708.0001.001. University of Michigan Library Digital Collections. Accessed May 5, 2024.

Pages

Rule 1

THe square root of any number being multi∣plied by that number, produceth the square root of the Cube of the number.

For √a multiplied by a produceth a√a, but a√a=√aaa for taking Equimultipli∣ces they will be equal, as if the first, namely a√a be muliplyed still by √a, the product is a√aa, that is aa. And if √aaa be multipli∣ed by √a it produceth √aaaa that is aa al∣so, wherefore a√a=√aaa. And therefore 3√3=√27 either of which is the cube of √3, and the like of all others.