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TO make a Triangle having its Sides equal to Three Right Lines given, provided that Two of them be greater than the Third.
Let it be proposed to make a Tri∣angle, having its Three Sides equal to the Three given Lines, AB, D, E, take with your Compasses the Line D, and putting one Foot thereof in the Point B, make an Arch: Then take in your Compasses the Line E, and put∣ting one Foot in the Point A, cross with the other Foot the former Arch in C; Draw the Lines AC, BC. I say that the Triangle ABC, is what you desire.
Demonstration. The Side AC is equal to the Line E, since it is the Ra∣dius of an Arch drawn on the Center A, equal in Length to the Line E, likewise the Side BC is equal to the Line D: Therefore the Three Sides AC, BC, AD, are equal to the Lines E, D, AB.