Sun (or any other Planet) in his Orbe. The Line, D, C, B, represents the planets true place, from the Center of the Earth, in the Meridian at, B. The Line, E, C, A, his apparent place, as it appeareth from us at E. The Angle of the Paralax of Altitude, is, A, C, B, (which is equal to E, C, D.) The Angle, A, E, I, is the Angle of the apparent Altitude, of the Planet above the Hori∣zon (which in this Example we suppose to be 27 degr. 40 min.) whose Complement is, Z, E, A, (62 deg. 20 min.) —Here you may see that the apparent Altitude of the Planets, is lesse from the Superficies (or place of Observation at E,) then from the Center of the Earth; (at D,) from which place the Planet in his Orb appears higher in the Meridian at B, then he doth from E, in the Meridian at A, so that the Angle of the Planets Paralaxis Altitudinis, is nothing else but the difference between the true and apparent Altitude, in the Meridian or Circle of Altitude.
Here note, that the nearer a Planet is to the Horizon and Center of the Earth, the greater is the Paralax there∣of. And hence it is, that the Moon (because of her Vi∣cinity to the Earth) hath the greatest Paralax of all the other Planets. And that's a main reason why we have so few Solar Eclipses, and those few have so little ob∣scurity. Because frequently her Southern Paralax ex∣ceeds her Northern Latitude (the greatest Eclipses hap∣pening alwayes when they are equal, and least when her Latitude is South) &c. These things being premised, I come next to practice: And for Illustration, I shall add an Example of either of the Luminaries, for to find their Paralaxis Altitudinis at any time Assign'd.
First, an Example in the Sun.
Suppose the Altitude of the Sun to be (by observati∣on) 27 deg. 40 min. and his distance from the Earth (by calculation) 101798 parts: I demand how much will his Paralax of Altitude (then) be? — To resolve this (and all such like) Questions. I return to this annexed Diagram, for Demonstrations sake, where, In the Triangle, C, D, E, we have known, [1] E, C,