OPERATION I. How to find the Proportion between the Perpendicular and its Shade.
COnsider the Northern or back part of the Globes Meridi∣an, which we will call hereafter the Quadrant of Propor∣tion, and which is not only devided like the Southern or fore-part into Degrees, but markt also (in relation to the affair in hand,) with several Figures, of which that next the Zenith is 17, and the remotest 188. And by the way you must take notice, that when you see a Cross behind any Figure, it signifies half an In∣teger more, so that 17 + is 17 Degrees and a half, 26 + is 26 and a half, &c. When you would therefore Operate, Turn the Southern or fore-part of the Meridian towards the Sun, 'till they be both in the same Plane, i. e. 'till the shade of the Pin in the Zenith falls directly upon the Quadrant of Proportion, and what Figure soever, (suppose 25) the shade of Extuberancy cuts, that will be the then Proportion between Perpendiculars and their Shades; for here you may take notice, that we ever suppose the Shade to be 100. Nay, if finding (by any of the former ways) the Sun's height to be (suppose) 14 Degrees, you rectify your Bead to 76 Degrees, or the Complement of it, you need only clap back your String, that is to say, draw it from the Zenith, over the Devisions of the afore-mention'd Quadrant, and then the Figures under the Bead (to wit 25) will shew you the required Proportion; In short, take but the Suns Height (any how) and reckon from the Zenith as many Degrees on your said Quadrant of Proportion, and the Fi∣gures at the end of your Account will give the Proportion sought for. Now if the Shade of Extuberancy, or the Bead marks not even Degrees for the Sun's Height, but (for Exam∣ples sake) 13.30′, and consequently falls between the Figures of 23 and 25 in the Quadrant of Proportion, you had best (to avoid all Calculation and Allowance) expect a Moment lon∣ger, for then the Sun's Height being even, and without Fra∣ction, you may operate as before.