The quadrature of the circle, the square root of two, and the right-angled triangle, by William Alexander Myers.

QUADRATURE OF THE CIRCLE. 113
1555613090938580753 -bultiplying this by tangent No. 7 we have 1099984565505235876 -5224779842639686625468648065798177627126514337489817601
3719716313591640029823644051645720435317842392159581760
secant No. 7.
By Case 7, the numerator of the secant is 15556130909385807535 -224779842639686625468648065798177627126514337489817601, and
the given radius is the 1/2
Then, by division, we have 155561309093858075352247798426396 --/2 = sine No. 7.
86625468648065798177627126514337489817601 = sne N 7
By Cae 7, 155561309093858075352247798426396866 -By Case, t scant s 109998456550523587637197163135916400 -25468648065798177627126514337489817601
and the radius is the
29823644051645720435317842392159581760 ad the radius s the
square root of two.
2199969131010471752743943262718328 -Then, by division, we have
155561309093858075352247798426396.
0059647288103291440870635684784319163520
86625468648065798177627126514337489817601 cosine No 7
278891833058856418130859753892 -By Case 6, the scant No. 6 s 197206306373463926398445507329 -4774401 15556130938580753522477984263968662546864806579 -9118880 - 109998456550523587637197163135916400298236440516 -8177627126514337489817602
45720435317842392159581760'. 1555613090938580753522477 -And, by Case 7, the secant No. 7 is 1555309 5873 77
10999845655052358763719716 -9842639686625468648065798177627126514337489817601
313591640029823644051645720435317842392159581760'
Therefore 1
10999845655052358763719716313591640029823644051 -64572043531784231 60 has been deducted from the assumed
645720435317842392159581760
radius, and twice that amount from the assumed diameter.
8