The Pell equation, by Edward Everett Whitford.

THE PELL EQUATION 33 modern symbols the proof is as follows: If aq2 + s = p, and aql2 + s1 = pi2, multiplying both members of the first equation by pl2, and substituting aq12 + sl for its equal, p12, when it is multiplied into s, we have aq2p12 + saql2 + SS1 = p2l2. In the second term of the left member substituting for s its equal p2 - aq,2 we have aq2p12 + aq2p - a2q2q12 + ss =p p2p2. Transposing the negative term, and adding == 2appiqqi to both sides, we have aq2p12 ' 2applqql + aq12p2 + ssi = p2pl2 = 2applqqi + a2q2q22, and a(qpl = qip)2 + SSI = (ppi — 1 aqql)2. Then x = ppi = aqql, y = qpl I qlp are solutions of the equation ay2 + ss1 = X2. By repeating these steps and by applying the last part of the rule ssl becomes equal to 1; that is, ay2 + 1 = X2 is solved. Then, as Bhaskara remarks, "by virtue of [a variety of] assumptions and by composition either by sum or difference, an infinity of roots may be found." Let us examine "the splendor point of the collected wisdom of the Hindus," the method of solution which 4

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Title
The Pell equation, by Edward Everett Whitford.
Author
Whitford, Edward Everett, 1865-
Canvas
Page 16
Publication
New York,: E. E. Whitford,
1912.
Subject terms
Diophantine analysis

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"The Pell equation, by Edward Everett Whitford." In the digital collection University of Michigan Historical Math Collection. https://name.umdl.umich.edu/abv2773.0001.001. University of Michigan Library Digital Collections. Accessed June 6, 2025.
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