The Stars have little or no alteration in their Latitude; but in their Longitude they move forward about 1 degr. 25 min. in a hundred years, which is 85′.
By Noble Ticho, his Tables of Longitude and Latitude of the Stars, rectified by himself, to the beginning of the year 1601.
The Latitude of the most bright Star Sirius in the Mouth of the great Dog, is 39 deg. 30 min. and his Longitude is 8 degr. 35 min. 30″ of ♋; I desire the Stars true Longitude, or to be rectified for this present year 1667.
You must work by the Rule of Proportion, thus, if 100 give 85 m. what shall 66 the difference in years betwixt 1601, and 1667 give? Multiply, and Divide, and the Quotient will be 56 m. 6″ added to the Longitude found in the Tables of the Stars in the second Book on the back-side the Nocturnal, which 8 deg. 35 min. 30″ makes 9 d. 31′ 36″ of Cancer, the Longitude of the Star Sirius this year 1667; and so work to find the Longitude of any other Star in any other year, past, or to come.
Take 9 deg. 32′ the Longitude of the Star, out of 90 deg. there remains 80 degr. 28′, his distance from the next Equinoctial Point; which being known, the First Rule is,
As the Radius 90 | 10 |
is to the Sign of the Stars Longitude from the next Equ. Point 80 d. 28 | CK 999396 |
So is the Co-Tangent of the Stars Latitude 39 deg. 30′ A ✶ | 1008389 |
to the Tangent of the fourth Ark 50 deg. 06 min. | 1007785 |
Compare this fourth Ark with the Arch of Distance betwixt the Poles of the Eclip∣tick, and the Poles of the World 23 deg. 31 min. if the Longitude and Latitude of the Star be alike, as in North Signs ♈ ♉ ♊ ♋ ♌ ♍, and the Latitude is on the North-side the Ecliptick; or if the Longitude be among the Southern Signs, as ♎ ♏ ♐ ♑ ♒ ♓, and the Latitude Southward; then shall the difference between the fourth Ark found, and the distance of the Poles 23 deg. 31′ be your fifth Ark.