PROBL. VIII. By the Line of Segments on the Rod or Staff, and also by a Table, How to find the Quantity of Liquor in a Cask that is part full.
SUppose you would know the Quantity of Liquor in a Cask whose depth at the Bong is 23 Inches, as before, and let the Liquor be in height 16 Inches, and the whole Cask to hold 44 85/190 Gallons.* 1.1
By the Line of Numbers on the Staff, the proportion will be, as the whole depth 23 Inch∣es is to the depth in Liquor 16 Inches, so is 1000 to 692 parts.
Which being sought for in the Segment-line on the Staff, you shall have in the Line by it 46 15/1••0 Gallons.
Now if you extend the Compasses from 63 to 46 75/100 Gallons; the same distance will reach once from 44 85/100, the Contents of the whole Cask to 33 6/10, that is, 33 6/10 Gall. of Wine in the Cask.* 1.2
Then by this Rule always as 63 Gallons is to 46 75/100 Gallons, so is 44 85/100 Gallons to 33 60/100 Gallons of Wine in the Cask.* 1.3
By the same Rule Work for Beer or Ale.
To Work this Arithmetically is somewhat tedious; wherefore I have here Calculated a Table whereby you may perform it very easy by help of the Rule of Three.
In the last Vessel whose depth at the Bong is 23 Inches, and depth in Liquor 16 Inches
As 23 is to 16, so is 10000 to 69 21 parts, which sought for in the nearest Number in the table of Segments you shall have against it 46 75/100 Gallons nearest.