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SECT. III. By the way of your Ship, and any 2 Angles of Position, to find the Distance of any Island, Cape, or Head-Land from you.
YOu have been shewed how to do it with a right-Angle of 45 degr. already; but with a little more trouble, you shall learn to do it by any 2 Angles what∣soever.
As for Example.
Suppose you were Sailing full South from A towards B, and from A should espy Land at C bearing 2 Points from you to the Westward, as S S W, or S W 22 deg. 30 min. and Sailing still upon your Course until you come to B, you observe the Place bears from you just 4 Points, or S W 45 degr. which is the double of the Angle observed at A. If in this manner you double any Angle; that is, let your first Angle be what it will, you must Sail until you have doubled that Number; then you may assure your self that the distance you have Sailed between A and B, is justly equal to the distance between B and C, B being the second Place where you made your last Observation, and C being the Place observed. So that if A B be 12 miles, B C is likewise 12 miles; and this you may do without further trouble or Calculation, and may lay it down by your Plain-Scale, as I have done this following Figure.
In all such Questions remember that the Angles at the second place of Observation, shall be either just the double, if you go nearer to the Place, or else just the half if you go further off than the Angle at the first place.* 1.1 Therefore the first Angle you may take at Random, no matter what it is, so you be careful to observe when you be just upon the double, or the half; so that by Calculation you may resolve it almost with as little trouble as a Right-Angle, which is made plain thus.* 1.2 In the Triangle ABC the acute Angle being the outward at B, being 45 degr. the obtuse or inward-Angle being the Complement thereof to 180 degr. must be 135 degr. and the Angle at A being 22 degrees 30 min. being added to this, makes 157 degr. 30 min. which Substracted from 180 degr. there must needs rest for the Angle at C 22 degr. 30 min. Now this Angle at C being equal to the Angle at A 22 degr. ½; therefore the side A B opposite to the one Angle, must needs be equal to the side B C opposite to the other Angle, as you see by this Case.* 1.3
As the Sine of the Angle A C B 22 degr. 30 min. | 958283 | ||
to the distance Sailed 12 mile AB | 107918 | ||
So is the Sine of the Angle CAB 22 degr. 30 min. | 958283 | ||
to the distance B C 12 miles. | 1066201 | ||
To find the distance A C | As the Sine of A C B 22 deg. 30 min. | 958283 | 107918 |
is to A B 12 miles. | 107918 | ||
So is the Co-sine of 135 d. which is 45 d. | 984948 | ||
to the distance from the first Place | 1092866 | ||
of Observation AC 22 miles. 17/199 parts. | 134583 |