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CHAP. V. How to find the just Quantity or Content of any Piece of Ground in any Form.
VVE have shewed in the fore-going Chap. how to Measure the Geometrical Square, the Parallelogram, the Triangle, Trapezium, the Circle, and the like. Now we will shew you how to cast up the Contents thereof more fully. Sup∣pose the fore-going Figure A, B, C, D, E, F, G, H, K, be a Plott drawn or Protracted by a Scale of 10 Perch in an Inch, and the exact Contents thereof is required. Now because it is an Angular Plott, neither in the form of a Square, Parallelogram, Trapezium, nor Triangle; therefore all such Plotts must be reduced into some of these forms: which to effect, I reduce the main Body of the Field into the Trapezium ACEK, and the residue of it into 5 Tri∣angles, as ABC, and CDE, and EFK, FHK, and FGH.
Now to know the just Quantity of Acres, Roods, and Perches the Field contains, I first measure the Trapezium ACEK, I measure with my Compasses the length of the perpendicular CO, and apply it to my Scale of 10 Perch in an Inch, and find it 14 Perch 88/100 parts; and likewise the perpendicular KP, and find it 10 Perches, 50 parts, which I add together, and they make 25 Perches 38 parts, which I Multiply in half the Base AE 16:43, and the Product is 416:99:34: Therefore if you cut off 4 Figures to the right-hand, you will have the Contents of the Trapezium 416 Perch, and cut off 2 Figures of the 4, and before the Comma is 99 parts of 100 of a Perch and 34/1••0 remains, which is not to be taken notice of.
In like manner for the Triangle ABC, I multiply half the perpendicular: 4∷75 by the whole Base 25 Perch 26 parts, or the whole perpendicular by half the Base, as be∣fore; it is all one, and the Product is the Content of the Triangle ABC 119 Perch 98 parts: and so likewise for the Triangle CDE, multiply half the base 9 Perch 52 by 12 Perch, and 20 DY the perpendicular, and the Product is 116 Perch 14: is the Contents of that Triangle. Likewise in the Triangle EFK, the length of the perpen∣dicular FR is 7 Perch: 00 and the half length of the base EK is 14 Perch 70, multi∣plyed as one whole Number, the Product is 102 Perch 90 parts 00: the Contents of that Triangle EFK: the 4 Triangle FHK perpendicular: 6 P. 10: H q base FK 11 P. 50 the Contents is 70 Perch: 15: the first Triangle FGH the perpendicular GS is 7 P. 92 and the base FH, the half thereof is 6 P. 50: multiplyed together, and the Product is 51 P. 48 parts for the Triangle FGH.
Lastly, I add the several sums together, and they give the Content of the whole Figure in Perches and 100 parts.
The Area or Con∣tent of the ☞ | 1 Trapezium | ACEK | 416:99 |
2 Triangle | ABC | 119:98 | |
3 The Triangle | CDE | 116:14 | |
4 Triangle | EFK | 102:90 | |
5 Triangle | FHK | 70:15 | |
6 Triangle | FGH | 51:48 | |
The Area or Content of the whole Field or Wood is | 877 P. 64 |