PROBL. VII. By the Course and Distance, and one Latitude, To find the other La∣titude, and Difference of Longitude.
SUppose I sail S. W. 3 deg. 33 min. Westerly, 1157 Leagues, and by observation find my self in the Latitude of 13 deg. 10 min. I require the Latitude of the Place from whence I came, and the Difference of Longitude between the two Places.
For the Difference of Latitude,
As the Radius B 90 deg. | 1000000 |
To the Distance sailed 1154 Leagues AE | 306222 |
So is the Sine-Complement of the Course E, 41 deg. 27 min. | 982083 |
To the D fference of Latitude 764 Leagues | 288315 |
Extend the Compasses from the Sine of 90 deg. to 1154 Leagues; the same will reach from the Sine of 41 deg. 27 min. to 764 Leagues, which converted into Degrees, is 38 deg. 12 min. the Difference of Latitude; which added to 13 deg. 12 min. the Latitude of the last Place, the Total is 51 deg. 22 min. the Latitude of the first Place required.
The Difference of Longitude is found as before in the third Problem, saying,
As the Radius, To the Difference of Latitude inlarged 934 5/10:
So is the Tangent of 48 d. 33 m. To the Difference of Longitude in Leagues 1058, which is 52 deg. 55 min.
Now to convert the Difference of Longitude found in any Latitude into Leagues, do it after this Example.
Suppose two Places in one Parallel of Latitude, as in the Parallel of 51 deg. 22 min. whose Difference of Longitude is 52 deg. 55 min. I require the Distance of those two Places.
As the Radius | 10 |
Is in proportion to the Compl. Sine of the Latitude 51 d. 22 m. | 979573 |
So is the Difference of Longitude 1058 Leagues | 302448 |
To the Distance in that Latitude 661 Leagues | 282092 |