Tangent Line QF 57 deg. 55 min. and lay from C to K, and draw the prick'd Line, and he will cut the Meridian PFS in B, the Latitude of Barbadoes, 13 deg. 10 min. through B draw the Circle LBN, so the Angle of Position is BLQ, whose measure is RO 67 deg. 51 min. that is, W. S. W. 21 min. Westerly; which taken off the Line of half Tangents of your Scale, and laid from C to Pole, and draw the Line from Pole through B, and it will cut the Limb in G: Therefore measure GL on the Line of Chords, you have 57 deg. for the Distance, or 1140 Leagues, or 3420 Miles.
To find the Distance in Questions of this Nature,
1 As the Radius, Is to the Co-sine of the Diff. of Longit. 52 d. 55 m. |
978030 |
So is the Co-tangent of the greater Latitude 51 deg. 22 min. |
990267 |
To the Tangent of the first Arch 25 deg. 44 min. |
968297 |
Take 25 deg. 44 min. from 76 deg. 50 min. the Complement of 13 deg. 10 min. the less Latitude, and the Remain is 51 deg. 6 min. the second Arch.
2 As the Sine of the first Arch 25 d. 44 m. |
995464 |
To find the Distance. |
Is to the Co-sine of the second Arch 51 d. 06 m. |
979793 |
So is the Sine of the greater Latitude 51 d. 22 m. |
989273 |
|
1969066 |
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To the Co-sine of the Distance 57 d. 00 m. |
973602 |
|
which is the nearest Distance in the Arch of a Great Circle, by 17 Leagues less than Mercator's Chart by the Rhomb, and less by 166 Leagues than by the Rhomb on the Plain Chart; which confirms this to be the nearest of all ways of Sailing betwixt any two Places.
To find the Angle of Position,
3 As the Sine of the Distance 57 deg. 00 min. |
992359 |
Is to the Sine of the Difference of Longitude 52 deg. 55 min. |
990187 |
So is the Co-sine of the Latitude 13 deg. 10 min. |
998843 |
Add the two last: Substract the first Numbers |
1989030 |
There remains the Sine of the Angle of Direct Position |
996681 |
Which is 67 deg. 51 min. from the South part of the Meridian Westward, as name∣ly, W. S. W, 20 m. Westerly.
Now to know the Distance and Angle of Position, you must put Barbadoes at B, on the West side of the Circle 13 deg. from AE, and draw the Parallel of Latitude 51 deg. 22 min. and lay off the Difference of Longitude from AE to F, and draw the Meridian-circle PFS, and it will cut the Parallel of Latitude in L; therefore from B draw the Circle from L to K: And if you follow your former Directions, BD will be the Measure of BL the Distance found, as before, 57 deg. 00 min. and LBP the Angle of Position, whose Measure is RG 36 deg. 26 min. and the Great Circles greatest Obliquity is CO 54 deg. 40 min. For,
4 As the Sine of the second Arch 51 deg. 6 min. |
989111 |
Is to the Sine of the first Arch 25 deg. 44 min. |
963767 |
So is the Tangent of Difference of Longitude 52 deg. 55 min. |
1012157 |
|
1975924 |
To the Tangent of the Direct Position 36 deg. 26 min. |
986813 |
From B towards L, which is 3 Points, 2 deg. 41 min. from the Meridian, namely, N. E. b. N. 2 deg. 41 min. Easterly, you must sail first from B towards L; but al∣ter your Course, still increasing toward the Eastward, as shall be shewed.