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The Use of the Quadrant in Astronomy.
The Latitude 51 Deg. 30 Min. Northward, and the Declination 20 Degrees, the difference of Ascension will be found thus.
First, Lay the Center Ear at E of the Index, over the Brass-Pin in the Center at A of the Quadrant, and lay the Edge of the Index to EL, to the Latitude of the Place on the Arch DM; and take of the Tangent-Line on the Edge of the Quadrant 20 Degrees the Sun's Declination; and lay that distance from the Center at A towards D, at that distance run with your Eye along the Parallel-Lines, and mark where it toucheth the Edge of the Index; there follow that Parallel-Line to the Arch, and reckon the Degrees from B to that Parallel-Line will be 27 Deg. 14 Min. the diffe∣rence of Ascension between the Sun's Rising and Setting, and hour of 6, according to the time of the Year.
The Degrees resolved into Hours and Minutes, is 1 Hour 49 Min. which is 4 of the Clock and about 11 Min, for the Sun Rising in the Morning, and 7 of the Clock 49 Min. his Setting in the Evening. In the same manner you must work for all La∣titudes.
So the Latitude being 51 Deg. 30 Min. and the place of the Sun in one Degree of Aquarius, that is 59 Degrees from the next Aequinoctial Point; therefore set the Ear at S of the Line of Sines of the Index on the Pin at A, and the Edge thereof to the Latitude, and reckon 59 Degrees the Sun's distance from the first Aequinocti∣al Point, from the Center to C along the Line of Sines of the Index; there note the Line that cuts the 59 Degrees following with your Eye, to the Degrees in the Arch, and reckon the Minutes of Degrees from M to the Edge of the Index, and you will find it about 33 Deg. 20 Min. the Amplitude required.
The Sun being either in 29 Degrees of Taurus, or 1 Deg. of Aquarius, or 1 Deg. of Leo, or 29 Deg. of Scorpio, that is 59 Degrees from the next Aequinoctial Point, To find his Declination do thus: Put the Ear of the Line of Sines on the Pin and Edge of the Index; put to 23 Deg. 30 Min. in the Sun's greatest Declination, reckoned from M on the Arch; then count the Sun's distance 59 Deg. on the Deg. of Sines of the Index: From the Center put one Foot of your Compasses by the Degree, with the other take the nearest distance to the Line or Side CM; apply that distance in the Line of Sines of the Index, from S along, and the other Foot will reach to 20 Degrees, the Declination required when the Sun is in the aforesaid Degrees and Sines. In like manner you must do for any other Degrees of the Sun's Place.