THe Triangle given is ABC, whose Quantity is 8 Acres, 0 Roods, and 16 Per∣ches; and it is desired to divide the same (by a Line drawn up parallel to the Side AC) into two Parts, viz. 4 Acres, 2 Roods, 0 Perches; and 3 Acres, 2 Roods, and 16 Perches.
First, Reduce both Quantities into Perches (as it is hereafter taught) and they will be 720, and 576; then reduce both these Numbers by abbreviation into the least proportional Term, viz. 5 and 4; and according to that proportion, divide the Base BC 54 of the given Triangle in E: then seek the mean Proportion between BE and BC, which Proportion is BF 36, of which 36 take the half, and thereby divide 576, the lesser Quantity of Perches, the Quotient will be HG 32, at which Pa∣rallel-distance from the Base, cut off the Line AB in H, from whence draw the Line HF parallel to the Side AC, which shall divide the Triangle given, according as it was required.
〈 math 〉〈 math 〉