THe Powers of Proportionals whether continuedly or discretely, such as the Squares, Cubes, &c. are also Proportional.
Continual Proportionals. | Discrete Proportionals. |
a ea e{powerof2}a e{powerof3}a | a ea b eb |
Squares aa e{powerof2}a{powerof2} e{powerof4}a{powerof2} e{powerof6}a{powerof2} | a{powerof2} e{powerof2}a{powerof2} b{powerof2} e{powerof2}b{powerof2} |
Cubes a{powerof3} e{powerof3}a{powerof3} e{powerof6}a{powerof3} e••a{powerof3} | a{powerof3} e{powerof3}a{powerof3} b{powerof3} e{powerof3}b{powerof3} |
Q E. D.
YOu founded in this Truth, 1. the Reason of the Multipli∣cation and Division of Surd Quantities: For since from the Nature and Definition of Multiplication, it is certain, that 1 is to the Multiplier as the Multiplicand to the Product (for the multiplicand being added as many times to it self as there are Units in the Multiplier, makes the Product) if the √5 is to be multiplied by √3, then as 1 to the √3, so the √5 to the Product; and, by the present Proposition, as 1 to 3, so 5 to the □ Product, i. e. to 15. Wherefore the Product is √15; and so the Rule for Multiplying Surd Quantities is this: Multiply the Quantity under the Radical Signs, and prefix a Radical Sign to the Product.(α) 1.1 Likewise since it is certain from the Nature of Division, that the Divisor is to the Dividend as 1 to the Quotient (for the Quotient expresses by its Units how many times the Divisor is contained in the Dividend) if the √15 is to be divided by √5, you'l have √5 to the √15 as 1 to the Quo∣tient, and, by the present Scholium, 5 to 15, as 1 to the □ of the Quotient, i. e, to 3. Therefore the Quotient is the Root of 3, and so the Rule of dividing Surd Quantities this; viz.