1. Denomination. CA=a as above, DA or DL=b, and putting x again for the sought Vy or VK, CV will be = a −x, DL or DR=b, and consequently DV=b+x, and DC=a−b, for which for brevity's sake we will put c. Now you'l have at least in Denomination in the ▵ CVD the three sides, so that aecording to Problem 9. the segment CW may be determined, for which in the mean while we will put y; then will DW=c+y, which is the same as DL−WL or Vy i. e. b−x.
2. For the Equation. If the □ CW=yy substract it from the □ CV = 〈 math 〉〈 math 〉, and you'l have the □ of the Perpendicular VW, 〈 math 〉〈 math 〉; and if the □ DW = 〈 math 〉〈 math 〉, substract it from the □ DV = 〈 math 〉〈 math 〉, and you'l have the same □ of the Perpendicular VW = 〈 math 〉〈 math 〉 Therefore 〈 math 〉〈 math 〉.