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TAKE the Altitude of the Star, and by his Declination and Altitude find the Hour (by the Twelfth Proposition) as if it were by the Sun, which I call the Star's Hour. Then comparing the Right Ascension of the Sun with the Right Ascen∣sion of the Star, you may come to find the Hour of the Night.
Example. Upon the 16. day of November, in the Morning, I took the Altitude of Arcturus, finding it to be 27 degr. 12 m. and his Declination (by the Table) I find to be 20 degr. 58 m. By help of these two and the Latitude I find the Star's Hour to be 72 degr. Then compare the Sun's Right Ascension with the Star's Right Ascension, and find his time of coming to the Meridian, as in the former Probl. the difference between the Star's Hour and his coming to the Meridian is the Hour of the Night. See the manner of the Operation.
d. | m. | |
The Right Ascension of Arcturus | 210 | 13 |
The Right Ascension of the Sun | 242 | 00 |
Adde to make Subt. | 360 | 00 |
The Sum is | 570 | 13 |
The Sun's Right Ascension substracted, rests | 328 | 13 |
From which take 180 degr. or 12 hours | 180 | 00 |
Rests | 148 | 13 |
The Star's Hour substracted | 72 | 00 |
Leaves the Hour of the Night | 76 | 13 |
Which converted into Time is 5 h. 5 m. and that is the Hour in the Morning.