IN the same Triangle, let there be given, the side QS 303, and QR 176, together with the angle QSR 24 degrees 20 minutes, and let it be required to finde the angle QRS, the proportion is,
As the Logarithm of the side QR 176, | 2,245513 |
Is to the sine of the angle QSR, 24 deg. 20 min. | 9,614944 |
So is the Logarithm of the side QS 303, | 2,481443 |
the sum of the second and third numbers | 12,096387 |
the first number substracted from the sum | 2,245513 |
To the sine of the angle QRS, | 9,850374 |
The neerest degree answering to this sine is 45 degrees 10 min. which is the quantity of the angle QRS, required.
Extend the Compasses from 176, to the sine of 24 degrees 20 minutes, the same extent will reach from 303 to 45 deg. 10 min. the angle QRS.
Or, the distance between 176 and 303, will be equall to the di∣stance between 24 degrees 20 minutes, and 45 deg. 10 min.