PROB. XIV. How to divide a Triangle into two parts, according to any proportion assigned, by a line drawn from any angle thereof, and to lay the lesser part towards any side assigned.
[illustration]
LEt ABC be a Triangle given, and let it be required to divide the same, by a line drawn from the angle A, into two parts, the one bearing proportion to the other, as the line F doth to the line G, and that the lesser part may be towards the side AB.
By the last Probleme divide the base of the Triangle BC in the point D, in proportion as the line F is to the line G, (the lesser part being set from B to D.) Lastly, draw the line AD, which shall divide the Triangle ABC in proportion as F to G; for,
- As the line F, is to the line G;
- So is the Triangle ADC; to the Triangle ABD.