TRiangles whose sides are proportional, are equianguler.
If the Triangles ABC, DEF, have their sides proportional, that is to say, if there be the same reason of AB to
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TRiangles whose sides are proportional, are equianguler.
If the Triangles ABC, DEF, have their sides proportional, that is to say, if there be the same reason of AB to
BC, as of DE to EF; as also if there be the same reason of AB to AC, as of DE to DF, the Angles ABC, DEF, A and D; C and F shall be equal. Make the Angle FEG equal to the Angle B; and EFG equal to the Angle C.
Demonstration. The Triangles ABC, EFG, have two Angles equal; they are thence equiangled (by the Cor. of the 32d. of the 1st.) and (by the 4th.) there is the same reason of DE to EF, as of EG to EF. Now it is supposed that there is the same reason of DE to EF, as of EG to EF. Thence (by the 7th. of the 5th.) DE, EG, are equal. In like manner DF, FG, are also equal, and (by the 8th. of the 1st.) the Triangles DEF, GEF, are equiangular. Now the Angle GEF was made equal to the Angle B: thence DEF is equal to the Angle B; and the Angle DFE, to the Angle C. So that the Triangles ABC, DEF, are equiangular.