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THat Line which divideth the Angle of a Triangle, into two equal parts, divideth its Base in two parts, which are in the same Reason to each other as are their Sides. And if that Line divideth the Base into parts proportional to the Sides, it shall divide the Angle into Two equally.
If the Line AD divideth the Angle BAC into Two equal parts; there shall be the same Reason of AB to AC, as of BD to DC. Continue the Side CA, and make AE equal to AB; then draw the Line EB.
Demonstration. The exterior Angle CAB is equal to the Two interior Angles AEB, ABE; which being equal (by the 5th. of the 1st.) seeing the Sides AE, AB, are equal; the Angle BAD, the half of BAC, shall be equal to one of them; that is to say to the Angle ABE. Thence (by the 27th. of the 1st.) the Lines AD, EB, are parallel; and (by the 2d.) there is the same Reason of EA, or AB to AC, as of BD to DC.