TO describe a Poligon like to another on a Line given.
There is proposed the Line AB, on which one would describe a Poligon like unto the Poligon CFDE. Having di∣vided the Poligon CFDE into Tri∣angles, make on the Line AB a Triangle ABH like unto the Triangle CFE; that is to say, make the Angle ABH equal to the Angle CFE, and BAH equal to FCE. So then the Triangles ABH, CFE, shall be equiangled (by the 32d. of the first.) make also on BH, a Triangle equiangled to FDE.
Demonstration. Seeing the Triangles which are parts of the Poligons, are equiangular, the two Poligons are equiangular. Moreover, seeing the Tri∣angles ABH, CFE, are equiangular, there is the same Ratio of AB to BH, as of CF to FE, (by the 4th.) In like manner, the Triangles HBG, EFD, being equiangular, there shall be the