The elements of Euclid, explained and demonstrated in a new and most easie method with the uses of each proposition in all the parts of the mathematicks / by Claude Francois Milliet D'Chales, a Jesuit ; done out of French, corrected and augmented, and illustrated with nine copper plates, and the effigies of Euclid, by Reeve Williams ...

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Title
The elements of Euclid, explained and demonstrated in a new and most easie method with the uses of each proposition in all the parts of the mathematicks / by Claude Francois Milliet D'Chales, a Jesuit ; done out of French, corrected and augmented, and illustrated with nine copper plates, and the effigies of Euclid, by Reeve Williams ...
Author
Dechales, Claude-François Milliet, 1621-1678.
Publication
London :: Printed for Philip Lea ...,
1685.
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Subject terms
Geometry -- Early works to 1800.
Mathematical analysis.
Link to this Item
http://name.umdl.umich.edu/A38722.0001.001
Cite this Item
"The elements of Euclid, explained and demonstrated in a new and most easie method with the uses of each proposition in all the parts of the mathematicks / by Claude Francois Milliet D'Chales, a Jesuit ; done out of French, corrected and augmented, and illustrated with nine copper plates, and the effigies of Euclid, by Reeve Williams ..." In the digital collection Early English Books Online 2. https://name.umdl.umich.edu/A38722.0001.001. University of Michigan Library Digital Collections. Accessed June 11, 2024.

Pages

PROPOSITION VI. PROBLEM.

To inscribe a Square in a Circle.

TO inscribe a Square in the Circle ABCD; draw to the Diameter AB, the Perpendicular DC, which may pass through the Center E. Draw also the Lines AC, CB, BD, AD; and you will have inscribed in the Circle the Square ACBD.

Page 192

Demonstration. The Triangles AEC, CEB, have their Sides equal, and the Angles AEC, CEB, equal, seeing they are Right, therefore the Bases AC, CB, are equal (by the 4th. of the 1st.) Moreover, seeing the Sides AE, CE, are equal, and the Angle E being Right, they shall each of them be semi-right, (by the 32d. of the 1st.) So then the Angle ECB is semi-right. And by consequence the Angle ACB shall be Right. It is the same of all the other Angles: there∣fore the Figure ACDB is a Square.

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