TWo Circles cut each other only in two Points.
If the two Circles ABD, ABFD, did cut each other in three Points, A,
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TWo Circles cut each other only in two Points.
If the two Circles ABD, ABFD, did cut each other in three Points, A,
B, D; seek (by the 2d.) the Center C of the Circles AE, BD, and draw the Lines CA, CB, CD.
Demonstration. The Lines AC, BC, DC, drawn from the Center C, to the Circumference of the Circle AE, BD, are equal: Now the same Lines are also drawn to the Circumference of the Circle AB, FB: thence (by the 9th.) the Point C shall be the Center of the Circle ABFD. So two Circles which cut each other shall have the same Center; which is contrary to the fifth Proposition.