TO Divide a Line given into two equal parts.
Let the Line AB be proposed to be Divided into Two equal parts, erect an Equilateral Triangle ABC, (by the 1st.) Divide the Angle ACB into two equal parts, (by the 9th.) I say the Line AB is Divided into two equal parts in the Point E: viz. That the Lines AE, EB, are equal.
Demonstration. The Triangles ACE, BCE, have the Side CE common, and the Si es CA, CB, equal, since the Triangle ACB is Equilateral: The Angles ACE, BCE, are equal, because the Angle ACB was Divided into two equal parts; therefore (by the 4th.) the Bases AE, EB, are equal.