stand, their Sum is 1098, which may be cal∣led a Divisor, and the whole Resolvend 46144, except 4 the place of Unites a Dividend; then draw another line.
Then seek how many times 1098 the Divi∣sor, can be had in 4614 the Dividend, it per∣mitteth but of 4, which subscribe in the Quo∣tient; Now Multiply the Triple square 108, by 4, it produceth 432, which in order subscribe under the Triple square 108: Then square 4, the figure last placed in the Quotient, whose square is 16; and Multiply it by 18 the Triple, it produceth 288, which subscribe under the Triple orderly, then subscribe the Cube of 4 (last placed in the Quotient) which is 64, in Order under the Resolvend. Then draw a ••ine underneath it, then add the three num∣bers, viz. 432, 288, and 64, together in such order as they are placed, their sum is 46144: Then draw another line under the Work, subtracting the said total 46144, from the Resol∣••end 46144, there remains 00, or nothing, which remainder subscribe under the last drawn ••ine, thus the work being finished I find the Cube root of 262144 the number propounded, to be 64: And thus you must have proceeded orderly step by step, if the number propounded ••ad arisen to some 3, 4, 8, 10, or more places, observing the direction prescribed untill all had ••bserved compleated.
NOTE.
BUT when a whole number, hath not a Cube-root expressible by any true or Rational