In the Triangle ADE, there is given the Side* 1.1 AE, 70° 00', the Side AD, 40° 00', and the An∣gle A 30° 28', Now the Angles D, and E, are re∣quired, which is thus found: take the Sum and Difference of the two Sides, and work as follow∣eth, saying.* 1.2
As S. ½ Z. crs. AE and AD, 55° co',
To S. ½ X. crs. AE and AD, 15 00.
So is Tc. ½ V. at A, 15 14,* 1.3
To T. ½ X. VV. D and E. 49 1430".