In the Triangle ABC, the side AB is 30 parts, and the side AC, is 49 78/100 parts, and the opposite Angle C, is 37° 00'.
First, To find the Angle at B, this is the A∣nalogy* 1.1 or Proportion.
As Log. cr. AB 30 parts,
To S. V. at C 37° 00'.
So Log. cr. AC 49 78/100 parts,
To Sc. V. B 93° 00', as was required to be found.
Now seeing that the Angle C, is 37° 00', and the Angle B, is 93° 00', which makes 120° 00', therefore must the Angle A be 50° 00'; the