In the Triangle ABC, the Base AB is 736 parts, and the Cathetus BC is 467 4/10 parts, and the Angle B, between them is a right angle o•• 90°: And here you may make either side of the Triangle, Radius, but I shall make BC the Cathetus Radius, and then to find the Angle at the Cathetus C, this is the Analogy or ••••••∣portion.
As Log. Cathet, BC 467 4/10 parts,* 1.1
To Radius or S 90°.
So Log. Base AB 736 parts,
To T. V. Cathe C 57° 35', as required.
Secondly, I find the other Angle, at A to be* 1.2 32° 25', it being the Complement, to C 57 35', unto 90°.
Thirdly, To find out the Hypothenuse AC this is the analogy or proportion.
As S. V. Cathe C. 57° 35',
To Log. Base AB 736 parts,
So Radius or S. 90°,
To Log. Hypothenuse AC 871 8/10 parts, 〈…〉〈…〉∣quired. But making the Base AB Radius, yo•• may find the Hypothenuse AC, by this anal〈…〉〈…〉 or proportion.