Astronomia Britannica exhibiting the doctrine of the sphere, and theory of the planets decimally by trigonometry, and by tables : fitted for the meridian of London ... / by John Newton ...

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Title
Astronomia Britannica exhibiting the doctrine of the sphere, and theory of the planets decimally by trigonometry, and by tables : fitted for the meridian of London ... / by John Newton ...
Author
Newton, John, 1622-1678.
Publication
London :: Printed for the author by R. and W. Leybourn, and are to be sold by Thomas Piercepoint ...,
1657.
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Subject terms
Astronomy -- Early works to 1800.
Planetary theory -- Early works to 1800.
Astronomy -- Mathematics -- Early works to 1800.
Link to this Item
http://name.umdl.umich.edu/A52255.0001.001
Cite this Item
"Astronomia Britannica exhibiting the doctrine of the sphere, and theory of the planets decimally by trigonometry, and by tables : fitted for the meridian of London ... / by John Newton ..." In the digital collection Early English Books Online. https://name.umdl.umich.edu/A52255.0001.001. University of Michigan Library Digital Collections. Accessed June 4, 2024.

Pages

To finde the second inequality of Mars.

We must have given, 1 The angle N A S, which is to be found by subducting the ☉ place from the eccentrick of ♂ reduced, or this from it, so that lesse then 6 signes may remain, this remainer is the Anomaly of the Orbe, and the complement thereof is the angle N A S, or the halfe, is the halfe sum of the opposite angles.

Example.
The eccentrick of ♂ reduced
257. 44576
The ☉ true place
154. 07347
Anomaly of the Orbe
103. 37229
Complement is N A S
76. 62771
Halfe Anomaly
51. 68614
These given with the sides N A & S A, I say,

As the greatest side N A146426 co. ar.4. 8343814
Is to Radius 10. 0000000
So is the lesser side S A1008955. 0038707
To the tang. of34. 568879. 8382521
Adde45 
As Radius  
To co-tang.79. 568879. 2650444
So tang. / sum51. 6861410. 1022929
To tang. ½ diff.13. 115369. 3673373
Summe64. 80150 angle A S N 
Differ.38. 57078 angle A N S 

Because the Suns place was subtracted from the eccentrick of ♂ redu∣ced, therefore the angle of elongation A S N 64. 80150 must be added to the ☉ place 154. 07347 and then the place of ♂ will be 218. 87497.

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