Astronomia Britannica exhibiting the doctrine of the sphere, and theory of the planets decimally by trigonometry, and by tables : fitted for the meridian of London ... / by John Newton ...

The meane motions of Jupiter.

Anno Christi.	Longitude ♃	Aphelion ♃	Node ♃
Years 1500	004. 50000	185. 54833	097. 93889
80	269. 04444	1. 98000	. 54722
6	182. 13667	. 14833	. 04111
Iuly	17. 62333	. 01444	. 00389
Dayes 16	1. 33000	. 00104	. 00030
Houres 18	. 06222
Parts 4564	. 00154
Mean motion.	474. 69820	187. 68414	98. 53141
Aphelion subt.	187. 68414	Rests Anomaly	287. 01406

The halfe of Jupiter first inequality, or his eccentricity, supposing his Semidiameter to be 100. 000 by the computation of Bullialdus is 4856, and the Semidiameter of the Earths Orbe 19138▪ and therefore to find ♃ Semidiameter, when the Semidiameter of the Earths Orb is 100. 000 the proportion is, As 19138. Is to 100. 000 so is 100. 000 to 522520, the Semidiameter required, which being doubled is the Diameter of the El∣lipsis,

or the side M E 1045040. And to find the eccentricity in the same parts, say, as 100. 000. is to 522520, so is 4856, to 2537••. the excentri∣city, and the double thereof. 50746 is M H the distance of the foces.

The complement of the Anomaly 72. 98594 is the angle A M E, and the halfe compl: 36. 49297, is the halfe sum of the opposite angles M E H and M H E.

The side M E	1045040
The side M H	50746
Sum	1095786 co. ar.	3. 9602744
Differ	994294	5. 9975147
Tang. ½ sum	36. 49297	9. 8690974
Tang. ½ differ	33. 87162	9. 8268865
Differ.	2. 62135 Angle M E H

Double differ. 5. 24270 Angle M B H or the Equatiō sought, and to be added to Jupiters mean longitude, the Anomaly being above a Semi-circle.

Jupiters mean longitude

114. 69820

Equation add

5. 24270

Jupiters eccentrick place

119. 94090

The Node subt.

98. 53141

Argument of Latitude.

21. 40949

By help whereof, and the angle of his greatest inclination 1. 36333, or E B 2379, we may find the reduction: but to find the parts of inclination in proportion to the given Radius 522520. say, As 100. 000. is to 2379, so is 522520 to 13619. the parts required.