Astronomia Britannica exhibiting the doctrine of the sphere, and theory of the planets decimally by trigonometry, and by tables : fitted for the meridian of London ...
Newton, John, 1622-1678.
4 Example.
If the distance from the Meridian be a just Quadrant, or 90 degrees Page 45 then omitting the two first proportions, the angle of Inclination may be found at one operation, by this analogie.
As the tangent of the Complement of declination, is to Radius.
So is the sine of the Pole, to the cotangent of the angle of inclination.
Let then the declination be 23, and the Pole 45. I say,
| As the tangent of H M | 67 | 10. 372148• |
| Is to Radius or the angle H M C | 90 | 10. 0000000 |
| So is the sine of M C | 45. | 9. 8494850 |
| To the Cotangent of H C M | 73. 30 | 9. 4773369 |
| Then as Radius, to the sine of M C | 45. | 9. 8494850 |
| So is the sine of H C M | 73. 30 | 9. 9812850 |
| To the sine of L M | 42. 63 | 9. 8307700 |
The height of the Pole above that Circle of position.
