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CHAP. VII. Shewing the manner of placing these upon the Rule.
FIrst, To set out the Diameter, you may take the nether part of the third column of the besil'd side, to set it on from the middle square stroke of the Rule. Then Gunther (in his Ʋse of the line of numbers in broad-measure, Prop. 11.) hath this proportion. Having the Circumference of a circle, to finde the Diameter: As 3143 to 1000, so is the Circumference, suppose it 47⌊13 to the Diameter 15: so that if you take 47⌊13 in your circle-scale, and set in that column from the middle square downward, so shall you set out 15 in that di∣stance, run that distance as oft as you can to the bottom of the Rule, which will be 4 times more, divide each of them into 3 equal parts, and the uppermost third into 5 equal, and num∣ber all the other great parts, save that with 5, 10, 15, &c. or if you will you may double 47⌊13, that is 94, 26, and take it from the circle-scale, set it there they will be 30; then half it, and they will be 15, then third it into fives.
2. To finde how to proportion the square within the circle by the Diameter. Let the Diameter be the Radius 1000, then will the chord of 90 degrees, which is the side of the square included, be the natural sine of half 90: viz. 45 degrees, the sine whereof is 707, therefore then because I would divide my scale into even sines, if therefore I take 7 times 5, that is 35, the proportion will be 707 . 1000 ∷ 35 . 49⌊50. or 49½: therefore if you take 49½ on the Diameter, and set it on the scale of chords, and divide it into 7 equal parts, and that part next the end into 5 small parts, numbring all but that with 5, 10, 15, &c. you have your scale of chords or square within the circle. Or (if you think it troublesome to divide it into 7 e∣qual parts) you may take 6 times 5, that is 30. and say 707 . 1000 ∷ 38 . 42⌊43, so then you may take 42⌊43 of the Diameter, and set on your scale of chords, and then divide each of them into halves, and each half in to 3 parts.