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To Cut the Rigging.
LET A be one Ship, and B the other, and B C the Rigging to be Cut in the Point E.
PROPOSITION I.
The greatest Range of the Piece in the Parabola, the Line of Impulse, the Ascent, or Height of the Rigging to be Cut, and the Angle of Elevation being given. To find the Horizontal Distance, or the Distance from one Ship to the other.
Then, In the Right Angled Tri∣angle ABC, the Angle BAC, the double of the greatest Range in the Parabola G, of the Culverin; the Line of Impulse AD, and the Per∣pendicular Ascent BE, or the Height of the Rigging to be cut with this Qualification, as G:DC::DC:CE being given. To find AB the Distance of the two Ships.
Then R:r + Z::S:BC, that is rS + Zs / R = BC in Diag. and Z2/G = CE in Diag. then Z2 + PG / G = BC in Diag. that is Z2 + PG / G = ZS + rS / R that is Z2R=ZGS + GrS − GPR.
G= 9374 the double of the greatest Range of the Culverin.
BE=P= 5 Paces, 5 foot to a Pace.
AD=r= 106
Sine of 8d=S= 13917
Rad. =R= 100000
DC=Z= 1371.31