The vse of which tables in Astronomi∣call matters, I haue here set downe as followeth.
1 To find out the declination of the Sunne, the place thereof being knowne.
MVltiply the Secant of the complement of the greatest declination by the totall sine, and diuide the product by the sine of the sunnes distance from one of the equinocti∣all points, the quotient is the Secant of an arch, whose complement is the declination of the sunne: for example, suppose that the sunne be entering into ♉ to finde the decli∣nation therof, first I multiply 25112030 the Secant of 66. degrées 32′· (which is the complement of 23. degrées 38′ the greatest declination) by 10000000. the product is 251120300000000. which being diuided by 5000000. (the sine of 30. degrées the sunnes distance from the equinoctial point) the quotient is 50224060. for which number I séeke in the table of Secants, the arch answering vnto it, is 78. degrées 32′· the complement whereof is 11. degrées 29′· which is the declination of the sunne.
2 Knowing the declination of the sunne how to finde his distance from the equinoctiall point, and so consequently his place in the Zodiacke.
MVltiply the Secant of the complement of the greatest decli∣nation by the totall sine, and deuide the product by the Se∣cant of the cōplement of the declination giuen, the quotient is the distance of the sun from the equinoctiall point. As for example, the declination of the sunne is supposed to be 11. degrées 29′· then to