The 2. Theoreme. The 2. Proposition. If the first be equemultiplex to the second as the third is to the fourth, and if the fifth also be equemultiplex to the second as the sixt is to the fourth: then shall the first and the fifth compo∣sed together be equemultiplex to the second, as the third and the sixt composed together is to the fourth.
SVppose that there be sixe quantities, of which let AB be the first, C the second, DE the third, F the fourth, BG the fifth, & EH the sixt: and suppose that the first, AB, be equemultiplex vnto the second, C, as the third, DE, is to the fourth, F: and let the fift, BG, be equemultiplex vnto the second, C, as the sixt, EH, is to the fourth, F. Then I say, that the first and the fifth composed together, which let be AG, is equemultiplex vnto the second, C, as the third and sixt composed together, which let be DH, is to the fourth, F. For forasmuch as AB is equemultiplex to C,* 1.1 as DE is