The 18. Theoreme. The 18. Proposition. If magnitudes deuided be proportionall: then also composed they shall be proportionall.
SVppose that the magnitudes deuided being proportionall, be AE, EB, CF, & FD, so that as AE is to EB, so let CF be to FD. Then I say, that composed also they shall be proportionall, that is, as AB is to BE, so is CD to DF. For if AB be not vnto BE, as CD is to FD,
then shall AB be vnto BE, as CD is either vnto a magnitude lesse then FD, on vnto a magnitude greater. Let it first be vnto a lesse, namely, to DG. And forasmuch as, as AB is to BE, so is CD to DG: the composed magnitudes therefore are proportio∣nall, wherefore deuided also they shall be proportionall (by y
e 17. of the first). Wherefore as AE is to EB, so is CG to GD. But by supposition as AE is to EB, so is CF to FD. Wherefore (by the
11. of the fift) as CG is to GD, so is CF to FD. Now then there are foure magnitudes, CG, GD, CF, and FD: of which the first CG is greater then the third CF. Wherefore (by the
14. of the fift) the second GD is greater then the fourth FD. But it is also put to be lesse then it: which is impossible. Wherfore it can not be that as AB is to BE, so is CD to a magnitude lesse then FD. In like sort may we proue, that it can not be so to a magni∣tude greater then FD. For by the same order of demonstration, it would follow that FD is greater then the sayd greater magnitude: which is impossible. Wher∣fore it must be to the selfe same. If therefore magnitudes deuided be proportio∣nall, then also composed they shall be proportionall: which was required to be proued.