vnder the lines AD and DC, is supposed to be equall to the square of the line DB. Wherefore the square of the line DE is equall to the square of the line DB. Wherefore also the line DE is equall to the line DB. And the line FE is equall to the line FB, for they are drawen from the centre to ye circumference. Now therefore these two lines DE and EF are equall to these two lines DB and BF, and FD is a common base to them both. Wherefore (by the 8. of the first) the angle DEF is equall to the angle DBF. But the angle DEF is a right angle. Wherefore also the angle DBF is a right angle. And ye line FB being produced, shall be the diameter of the circle. But if from the end of the di∣ameter of a circle be drawen a right line making right angles, the right line so drawen toucheth the circle (by the Correllary of the 16. of the third). Wherfore the right line DB toucheth the circle ABC. And the like demonstration will serue if the centre be in the line AC. If therefore without a circle be taken a cer∣taine point, and from that poynt be drawen to the circle two right lines, of which the one doth cut the circle, and the other falleth vpon the circle, and that in such sort, that the rectangle parallelogramme which is contayned vnder the whole right line which cutteth the circle, and that portion of the same line that lieth be∣twene the poynt and the vtter circumference of the circle, is equall to the square made of the line that falleth vpon the circle: then the line that so falleth vpon the circle shall touch the circle: which was required to be proued.
¶ An other demonstration after Pelitarius.
Suppose that there be a circle BCD, whose
centre let be
E: and take a point without it, name∣ly,
A: And frō the poynt
A drawe two right lines
ABD, and
AC: of which let
ABD cut the circle in the poynt
B, & let the other fall vpon it. And let that which is contained vnder the lines
AD and
AB, be equall to the square of the line
AC. Then I say, that the line
AC toucheth the circle. For first if the line
ABD do passe by the centre, draw the right line
CE. And (by the 6. of the second) that which is contayned vnder the lines
AD and
AB together with the square of the line
EB, that is, with the square of the line
EC (for the lines
EB and
EC are equall) is equall to the square of the line
AE. But that which is contained vnder the lines
AD and
AB, is supposed to be equall to the square of the line
AC: Wherefore the square of the line
AC together with the square of the line
CE, is equall to the square of the line
AE. Wherefore (by the last of the first) the angle at the point
C is a right angle. Wherfore (by the 18. of this boke) the line
AC toucheth the circle.