An addition of Pelitarius.
To reduce two vnequall squares to two equall squares.
Suppose that the squares of the lines AB and AC be vnequall. It is required to re∣duce them to two equall squares. Ioyne the two lines AB and AC at their endes in such sort that they make a right angle BAC. And draw a line from B to C. Then vppon the two endes B and C make two angles eche of which may be equal to halfe a right an∣gle (This is done by erecting vpon the line BC perpē∣diculer
lines, from the pointes
B and
C: and so (by the 9. proposition) deuiding
••che of the right angles into two equall partes): and let the angles
BCD and
CBD be either of thē halfe of a right angle. And let the lines
BD and
CD concurre in the point
D. Then
I say that the two squares of the sides
BD and
CD, are equall to the two squares of the sides
AB and
AC. For (by the 6 proposition) the two sides
DB and
DC are equall, and the angle at the pointe D is (by the 32. proposition) a right angle. Wherefore the square of the side
BC is e∣qual to the squares of the two sides
DB and
DC (by the 47. proposition): but it is also equall to the squares of the two sides
AB and
AC (by the self same proposition) wher∣fore (by the common sentence) the squares of the two sides
BD and
DC are equall to the squares of the two sides
AB and
AC: which was required to be done.