An other conuerse of the same proposition.
If a parallelogramme be the double of a triangle, being both within the selfe same parallel lines:* 1.1 then are they vpon one and the selfe same base, or vpon equall bases. For if in that case their ba∣ses should be vnequal, then might straight way be proued, that the whole is e∣quall to his part: which is impossible.
A trapesium hauing two sides onely parallel lines,* 1.2 is eyther more then dou∣ble, or lesse then double to a triangle contayned within the selfe same parallel lines, and hauing one and the selfe same base with the trapesium, or table. ••ust the double it cannot be, for then it should be a parallelogramme. A trapesium ha∣uing two sides parallels hath of necessitie the one of them longer then the other: for if they were equall then should the other two sides enclosing them be also e∣quall (by the 33. proposition.) If the greater side of the trapesium be the base of the triangle, then shal the trapesium be lesse then the double of the triangle And if the lesse side of the trapesium be the base of the triangle then shall the trapesi∣um be greater then the triangle.
For suppose that ABCD be a trapesium,* 1.3 and let
Agayne let the triangle haue to his base the side