the line CD, put the line FA equal, & vnto the line DE let the line AB be equal, & vn∣to the line EC put the line BG equal. And making the cētre the point A, & the space AF, describe a circle KF. And agayne making the centre the point B and th•• space BG de∣scribe
an other circle
••L: which shal of necessitie cut the one the other, as we haue be∣
••ore proued. Let them cut the one the other in the pointes M & N. And draw these right lin
••s AN, AM, BN, and BM. And forasmuch as FA is equall to AM
•• and also to AN (by the definition of a circle) but CD is equall to FA, wherfore the lines AM and AN are ech
•• equall to the line
DC. Ag
••yne forasmuch as
BG, is equall to BM, and to BN, and
BG is equall to
CE: therfore either of these lines BM and BN is equall to the line CE. But the line BA is equall to the line DE. Wherfore these two lines BA & AM, are equall to these two lines
D E and DC, the one to the other, and the base BM is equal to the base
CE. Wherfore (by the 8. proposition) the angle MAB, is equall to the angle at the point
D. And by the same reason the angle NAB, is equall to the same angle at the point
D. Wherfore vpon the right line geuen
AB, and to the point in it geuen
A, is de∣scribed a rectiline angle on either side of the line
AB: namely, on one side the rectiline angle NAB, and on the other side the rectiline angle MAB, either of which is equall to the rectiline angle geuen
CDE: which was required to be done.