¶ The 4. Proposition. The 4. Probleme. In an Octohedron geuen, to describe a Cube.
SVppose that the Octohedron geuen be ABGDEZ. And let the two pyramids thereof be ABGDE, and ZBGDE. And take the centres of the triangles of the pyramis ABGDE, that is, take the centres of the circles which containe those triangles: and let those centres be the point••s T, I, K, L. And by these centres let there be drawen parall••l lines ••o the sides of the
square BGDE: which parallel
••ig
•••• lin
•••• let be MTN, NLX, XKO, & OIM. And forasmuch as th
••se parallel right lines do (by the 2. of the sixth) cut the equall right lines AB, AG, AD, and AE, proportionally, therfore they concurre in the pointes M, N, X, O. Wherefore the right lines MN, NX, XO, and OM, which subtend equall an∣gles set at the point A, & contained vnd
••r
••quall right lines, are equall (by the 4. of the first). And moreouer, seing that they are parallels vnto the lines BG, GD, DE, E
••, which make a square, therefore MNXO is also a square, by the 10. of the eleuenth. Wherefore also, by the 15. of the
••ame, the square MNXO is parallel to the squar
•• BGDE. For all t
••e right lines touch the one the other in the pointes of their sections. From the centres T, I, K, L, drawe these right lines TI, IK, KL, LT
•• And drawe the right line AIC. And forasmuch as I is the centre of the equilater triangle ABE, therefore the right line AI being extended, cutteth the right line BE into two equall partes (by the Corollary of the 12. of the thirtenth). And forasmuch as MO is a parallel to BE, therefore the triangle AIO is like to the whole triangle ACE (by the Corollary of the 2. of the sixth). And the right line MO is diuided into two equall partes in the point I (by the 4. of the sixth). And by the same reason may we proue, that the right lines MN, NX, XO, are diuided into two equall