Two circles being geuen, to finde one circle equall to them both.
Suppose the two circles geuē, haue their diameters A•• & CD. I say that a circle must be ••ound equall to the two circles whose diameters are A•• and CD: vnto the
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Two circles being geuen, to finde one circle equall to them both.
Suppose the two circles geuē, haue their diameters A•• & CD. I say that a circle must be ••ound equall to the two circles whose diameters are A•• and CD: vnto the
Hereby it is made euident, that in all triangles rectangle, the circles, semicircles, quadrants, o•• any other portions of circles described vpon the subtendent line, is equall to the two circles, semicircles, quadrants, or any two other like portions of circles, described on the two lines comprehending the right angle, like to like being compared.
For like partes haue that proportion betwene them selues, that their whole magnitudes haue, of which they are like partes, by the 15. of the fifth. But of the whole circles, in the former probleme it is euident: and therefore in the fornamed like portions of circl••s, it is a true consequent.
By the former probleme, it is also manifest, vnto circles three, fower, fiue, or to how many so euer one will geue, one circle may be geuen equall.
For if first, to any two, by the former probleme, you finde one equall, and then vnto your found circle and the third of the geuen circles, as two geuen circles, finde one other circle equall, and then to that second found circle, and to the fourth of the first geuen circles•• as two circles, one new circle be found equall, and so proceede till you haue once cuppled orderly, euery one of your propoūded circles (except the first and second already doone) with the new circle thus found for so the last found circle is equall to all the first geuen circles. If ye doubt, or sufficiently vnderstand me not: helpe your selfe by the discourse and demonstration of the last proposition in the second booke, and also of the 31. in the sixth booke.
Cons••ruction.
Demonstra∣tion.