from the point H to the point A. Now I say that the so••ide angle A contained vnder the su∣perficiall angles BAL, BAH, and HAL is equall to the solide angle D contained vnder the superficiall angles EDCEDF, and FD••. Le•• the the li••es AB and DE be put e∣quall, and draw these right lines. HB, BK, FE, and EG. And forasmuch as the line FG is erected perpendicularly to the ground superficies, therfore by the 2. definition of the eleuenth, the lin•• FG is also erected perpendicularly to all the right lines that are in the ground super∣ficies and touche it. Wherfore either of these angles FGD and FGE is a right angle, and by the same reason also either of the angles HKA and HKB is a right angle. And foras∣much as these two lines KA & AB are equall to these two lines GD & DE, the one to the other, and they containe equall
angles (by construction). Wher¦fore (by the 4. of the first) the base KB is equall to the base EG, and the line KH is equall to the line GF, and they cōprehēd right angles. Wherfore the line BH is equall to the line FE. Agayne, forasmuch as these two lines AK and KH are equal to these two lines DG and GF, and they containe right angles. Wherfore y
e base AH is (by the 4. of the first) equall to the base DF. And the line AB is equall to the line DE. Wherfore these two lines AB and AH are equall to these two lines FD and DE, and the base BH is equall to the base FE. Wherfore (by the 8. of the first) the angle BAH is equall to the angle EDF. And by the same reason also the angle HKL is equall to the angle FGC. Wherfore if we put these lines AL and DC equall, and draw these right lines KL, HL, GC, and FC: for∣asmuch as the whole angle BAL is equall to the whole angle EDC, of which the angle BAK is supposed to be equall to the angle EDG, therfore the angle remayning, namely, KAL is equall to the angle remayning GDC. And forasmuch as these two lines KA and AL are equall to these two lines GD and DC, and they containe equall angles, therefore by the 4. of the first, the base KL is equall to the base GC, and the line KH is equall to the line GF, wherfore thes
•• ••wo lines LK and KH are equall to these two lines CG and GF, and they cō∣taine right angles. Wherfore the base HL is (by the 4. of the first) equal to the base FC. And forasmuch as these two lines HA and AL are equall to these two FD and DC, and the base HL is equall to the base FC, therfore (by the 8. of the first) the angle HAL is equall to the angle FDC, and by construction, the angle BAL is equall to the angle EDC. Wherefore vnto the right line geuen, and at the point in it geuen, namely, A, is made a solide angle equal to the solide angle geuen D: which was required to be done.
In thes•• two 〈…〉〈…〉
here put, you may in 〈◊〉〈◊〉 clearely concerne the ••••••••mer construction and d••••monstratiō, if ye erect pe••••pendicularly vnto the ground superficies the tri∣angles ALB and DCE, & eleuate the triangles ALH and DCF that the lynes