¶ The 24. Probleme. The 90. Proposition. To finde out a sixth residuall line.
TAke a rational line and let the same be A,* 1.1 And
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TAke a rational line and let the same be A,* 1.1 And
of the line FG be to the square of the line GH. Now therfore for that as the number E is to the nūber BC,* 1.2 so is the square of the line A to the square of the line FG, therfore the square of the line A is commensurable to the square of the line F G. Wherfore the square of the line FG is rationall, and the line FG is also rationall. And for that the number E hath not to the number BC that proportion that a square number hath to a square number, therfore the line A is incommensurable in length to the line FG. Againe for that as the number BC is to the number CD, so is the square of the line FG to the square of the line GH, therefore the square of the line FG is commensurable to the square of the line GH. But the square of the line FG is rationall, wherfore the square also of the line GH is rationall, wherfore the line GH is also rationall. And for that the number B•• hath not to the number CD that propor∣tion that a square number hath to a square number, therfore the line FG is incommensura∣ble in length to the line GH, and they are both rationall. Wherefore the lines FG and GH are rationall commensurable in power onely. Wherfore
* 1.3There is also a certayne other redier way to finde out euery one of the forsayd sixe residu∣all lines which is after this maner. Suppose that it were required to finde out a first residuall line: Take a first binomiall line AC, & let the greater name
Construction.
Demonstra∣tio••.
An other more redie way to finde out the sixe re∣siduall lines.