¶ The 22. Probleme. The 88. Proposition. To finde out a fourth residuall line.
TAke a rationall line and let the same be A: and vnto it let the line BG be commensurable in length. Wherefore the line BG is rationall. And take two numbers DF and FE, and let them be such that the whole number, namely, DE haue to neither of the numbers DF and FE that proportion that a square number hath to a square
number. And as the number
DE is to the number
EF, so let the square of the line
BG be to the square of the line
GC: wherefore the square of the line
BG is com∣mensurable to the square of the line
GC, wherefore also the square of the line
GC is rationall, and the line
GC is also rationall. And for that the number
DE hath not the number
EF that proportion that a square number hath to a square number, therefore the line
BG is incom∣mensurable in length to the line
GC. And they are both rationall: wherefore the line
BC is a residuall line. I say moreouer that it is a fourth residuall line. For forasmuch as the square of the line
BG is greater then the square of the line
GC, vnto the square of the line
BG let the squares of the lines
CG and
H be equall. And for that as the number
DE is to the number
EF, so is the square of the line
BG to the square of the line
GC, therefore by con∣uersion of proportion as the number
DE is to the number
DF, so is the square of the line
BG to the square of the line
H. But the numbers
DE and
DF haue not the one to the other that porportion that a square number hath to a square number. Wherefore the line
BG is incommensurable in length to the line
H. Wherefore the line
BG is in power more then