Here is the Assumpt (of the foregoing Proposition) confirmed.
Now let vs declare how as the line HF is to the line FE, so to make the line FK to the line EK. The line CD is greater then the line BD by supposition. Wherefore also the line HF is greater then the line FE (by alternate proportion, and the 14. of the fifth).* 1.1 From the line HF take away the line FL equall to the line FE. Wherefore the line remayning, name∣ly, HL, is lesse then the line HF, for the line HF
Two vnequall right lines being propounded, to adioyne vnto the lesse, a right line, which takē with [ 1] the lesse (as one right line) shall haue the same proportion, to the line adioyned, which, the greater of the two propounded, hath to the lesse.
The construction and demonstration hereof, is worde for worde to be taken, as it standeth here before: after these wordes: The line HF is greater then the line FE.
It is therefore euident, that thus are three right lines (in our handling) in continuall proportion: [ 2] it is to weete, the greater, the lesse and the adioyned, make the first, the lesse with the adioyned, make the second: and the adioyned line is the third.
This is proued in the beginning of the demonstration, after the Assumpt vsed.