¶ The 35. Theoreme. The 35. Proposition. If there be numbers in continuall proportion how many soeuer, and if from the second and last be taken away numbers equall vnto the first, as the ex∣cesse of the second is to the first, so is the excesse of the last to all the nūbers going before the last.
SVppose that these numbers A, BC, D, and EF, be in continuall proportion be∣ginning at A the least. And from BC, which is the second, take away CG equall vnto the first, namely, to A, and likewise from EF the last take away FH e∣quall also vnto the first, namely, to A. Then I say, that as the excesse BG is to A the first, so is HE the excesse, to all the numbers D, BC, and A, which go before the last number, namely, EF.* 1.1 Forasmuch as EF is the greater (for the second is supposed greater then the first) put the number FL equall to the number D, and likewise the number FK equall to the number BC. And forasmuch as FK is equall vnto CB, of which FH is equall vnto GC, therefore the residue HK is equall vnto the residue GB. And for that as the whole F••, is to the whole FL, so is the part taken away FL, to the part taken away FK, therefore the residue LE is to